mm: memblock: show all region flags in debugfs

Commit 493f349e38 ("memblock: Add flags and nid info in memblock
debugfs") made memblock_debug_show() stop after finding the first set
flag. A memblock region can carry multiple flags, so the remaining flags
are hidden from debugfs.

Walk all bits in the region flags and print every set flag separated by
"|". Keep walking beyond flagname[] so that a set flag without a known
name is reported as UNKNOWN rather than silently ignored.

Fixes: 493f349e38 ("memblock: Add flags and nid info in memblock debugfs")
Signed-off-by: Meijing Zhao <zhaomeijing@lixiang.com>
Link: https://patch.msgid.link/20260902075944.3742866-1-zhaomeijing100@gmail.com
Signed-off-by: Mike Rapoport (Microsoft) <rppt@kernel.org>
This commit is contained in:
Meijing Zhao
2026-09-09 20:26:42 +03:00
committed by Mike Rapoport (Microsoft)
parent cee9395acd
commit e2d5b01f87
+11 -7
View File
@@ -2908,14 +2908,18 @@ static int memblock_debug_show(struct seq_file *m, void *private)
else
seq_printf(m, "%4c ", 'x');
if (reg->flags) {
for (j = 0; j < count; j++) {
if (reg->flags & (1U << j)) {
seq_printf(m, "%s\n", flagname[j]);
break;
}
unsigned int flags = reg->flags;
bool first = true;
for (j = 0; flags; j++, flags >>= 1) {
if (!(flags & 1))
continue;
if (!first)
seq_putc(m, '|');
seq_puts(m, j < count ? flagname[j] : "UNKNOWN");
first = false;
}
if (j == count)
seq_printf(m, "%s\n", "UNKNOWN");
seq_putc(m, '\n');
} else {
seq_printf(m, "%s\n", "NONE");
}